What are the solutions to the equation x^2+(x+1)^2=841 ?

The solutions to the equation x^2+(x+1)^2=841 are x=20,x=-21

Find the zeros of x^2+(x+1)^2=841

The zeros of x^2+(x+1)^2=841 are x=20,x=-21

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x^{2} + (x + 1)^{2} = 841

x = 20, x = - 21

Solution steps

x^{2} + (x + 1)^{2} = 841

Expand

x^{2} + (x + 1)^{2} : 2 x^{2} + 2 x + 1

2 x^{2} + 2 x + 1 = 841

Move

841

to the left side

2 x^{2} + 2 x - 840 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 840 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 840) = 82

x_{1, 2} = \frac{- 2 \pm 82}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 82}{2 \cdot 2}, x_{2} = \frac{- 2 - 82}{2 \cdot 2}

x = \frac{- 2 + 82}{2 \cdot 2} : 20

x = \frac{- 2 - 82}{2 \cdot 2} : - 21

The solutions to the quadratic equation are:

x = 20, x = - 21

b^{2} = 8.7

- x^{2} - 5 x = 0

x (9 x - 4) = 13

X^{2} + 2 X - 3 = 0

24 x^{2} - 8 x = 0

What are the solutions to the equation x^2+(x+1)^2=841 ?
The solutions to the equation x^2+(x+1)^2=841 are x=20,x=-21
Find the zeros of x^2+(x+1)^2=841
The zeros of x^2+(x+1)^2=841 are x=20,x=-21