What are the solutions to the equation 3g^2-24g+27=0 ?

The solutions to the equation 3g^2-24g+27=0 are g=4+sqrt(7),g=4-sqrt(7)

Find the zeros of 3g^2-24g+27=0

The zeros of 3g^2-24g+27=0 are g=4+sqrt(7),g=4-sqrt(7)

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3 g^{2} - 24 g + 27 = 0

g = 4 + 7, g = 4 - 7

Decimal Notation

g = 6.64575 \dots, g = 1.35424 \dots

Solution steps

3 g^{2} - 24 g + 27 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 \cdot 27}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 \cdot 27 = 67

g_{1, 2} = \frac{- ( - 24 ) \pm 6 7}{2 \cdot 3}

Separate the solutions

g_{1} = \frac{- ( - 24 ) + 6 7}{2 \cdot 3}, g_{2} = \frac{- ( - 24 ) - 6 7}{2 \cdot 3}

g = \frac{- ( - 24 ) + 6 7}{2 \cdot 3} : 4 + 7

g = \frac{- ( - 24 ) - 6 7}{2 \cdot 3} : 4 - 7

The solutions to the quadratic equation are:

g = 4 + 7, g = 4 - 7

a^{2} - 15 a + 56 = 0

n^{2} - 363 n + 720 = 0

2342.2 = 0.68 \cdot 2.14 \cdot 100 \cdot x \cdot (9.5 - 0.4 \cdot x)

x (x - 9) = 22

7 x - 12 = x^{2}

What are the solutions to the equation 3g^2-24g+27=0 ?
The solutions to the equation 3g^2-24g+27=0 are g=4+sqrt(7),g=4-sqrt(7)
Find the zeros of 3g^2-24g+27=0
The zeros of 3g^2-24g+27=0 are g=4+sqrt(7),g=4-sqrt(7)