What are the solutions to the equation ax^2+bxc=0 ?

The solutions to the equation ax^2+bxc=0 are x=0,x=-(bc)/a ;\quad a\ne 0

Find the zeros of ax^2+bxc=0

The zeros of ax^2+bxc=0 are x=0,x=-(bc)/a ;\quad a\ne 0

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a x^{2} + b x c = 0

x = 0, x = - \frac{b c}{a}; a \neq = 0

Solution steps

a x^{2} + b x c = 0

Write in the standard form

a x^{2} + b x + c = 0

a x^{2} + b c x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- b c \pm ( b c ) ^{2} - 4 a \cdot 0}{2 a}

Simplify

(b c)^{2} - 4 a \cdot 0 : b c

x_{1, 2} = \frac{- b c \pm b c}{2 a}; a \neq = 0

Separate the solutions

x_{1} = \frac{- b c + b c}{2 a}, x_{2} = \frac{- b c - b c}{2 a}

x = \frac{- b c + b c}{2 a} : 0

x = \frac{- b c - b c}{2 a} : - \frac{b c}{a}

The solutions to the quadratic equation are:

x = 0, x = - \frac{b c}{a}; a \neq = 0

3 x^{2} - 8 = 19

k^{2} = 121

x, x^{2} = 1 + y

9 r^{2} + 6 r = 1

2 x^{2} + x = 5 x^{2} - 2 x

What are the solutions to the equation ax^2+bxc=0 ?
The solutions to the equation ax^2+bxc=0 are x=0,x=-(bc)/a ;\quad a\ne 0
Find the zeros of ax^2+bxc=0
The zeros of ax^2+bxc=0 are x=0,x=-(bc)/a ;\quad a\ne 0