What are the solutions to the equation 3y^2=-16 ?

The solutions to the equation 3y^2=-16 are y= 4/(sqrt(3))i,y=-4/(sqrt(3))i

Find the zeros of 3y^2=-16

The zeros of 3y^2=-16 are y= 4/(sqrt(3))i,y=-4/(sqrt(3))i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 y^{2} = - 16

y = \frac{4}{3} i, y = - \frac{4}{3} i

Solution steps

3 y^{2} = - 16

Divide both sides by

3

y^{2} = - \frac{16}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - \frac{16}{3}, y = - - \frac{16}{3}

- \frac{16}{3} = \frac{4}{3} i

- - \frac{16}{3} = - \frac{4}{3} i

y = \frac{4}{3} i, y = - \frac{4}{3} i

- 3 x - 4 = 3 x^{2} - 13 x + 3

2 x^{2} - x - 10 = - 2

x, y = - 0.000009 x^{2} + 0.0104 x + 0.3928

20 x^{2} - 80 x + 75 = 0

- 2 x^{2} - 12 x + 32 = 0

What are the solutions to the equation 3y^2=-16 ?
The solutions to the equation 3y^2=-16 are y= 4/(sqrt(3))i,y=-4/(sqrt(3))i
Find the zeros of 3y^2=-16
The zeros of 3y^2=-16 are y= 4/(sqrt(3))i,y=-4/(sqrt(3))i