What are the solutions to the equation 5y^2+15y=0 ?

The solutions to the equation 5y^2+15y=0 are y=0,y=-3

Find the zeros of 5y^2+15y=0

The zeros of 5y^2+15y=0 are y=0,y=-3

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5 y^{2} + 15 y = 0

y = 0, y = - 3

Solution steps

5 y^{2} + 15 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

1 5^{2} - 4 \cdot 5 \cdot 0 = 15

y_{1, 2} = \frac{- 15 \pm 15}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- 15 + 15}{2 \cdot 5}, y_{2} = \frac{- 15 - 15}{2 \cdot 5}

y = \frac{- 15 + 15}{2 \cdot 5} : 0

y = \frac{- 15 - 15}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

y = 0, y = - 3

0 = 5 x^{2} - 2 x + 6

\frac{1}{2} (2)^{0}

12 - \frac{1}{2} x = x

5 x + 7 > - 13

x^{3} + 2 x^{2} - 7 x - 14

What are the solutions to the equation 5y^2+15y=0 ?
The solutions to the equation 5y^2+15y=0 are y=0,y=-3
Find the zeros of 5y^2+15y=0
The zeros of 5y^2+15y=0 are y=0,y=-3