What are the solutions to the equation 6=x^2-10x ?

The solutions to the equation 6=x^2-10x are x=5+sqrt(31),x=5-sqrt(31)

Find the zeros of 6=x^2-10x

The zeros of 6=x^2-10x are x=5+sqrt(31),x=5-sqrt(31)

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6 = x^{2} - 10 x

x = 5 + 31, x = 5 - 31

Decimal Notation

x = 10.56776 \dots, x = - 0.56776 \dots

Solution steps

6 = x^{2} - 10 x

Switch sides

x^{2} - 10 x = 6

Move

6

to the left side

x^{2} - 10 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 6) = 231

x_{1, 2} = \frac{- ( - 10 ) \pm 2 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 31}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 31}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 31}{2 \cdot 1} : 5 + 31

x = \frac{- ( - 10 ) - 2 31}{2 \cdot 1} : 5 - 31

The solutions to the quadratic equation are:

x = 5 + 31, x = 5 - 31

x, - x^{2} - 4 x + 12 = 0

5 x = 9 x^{2}

n^{2} = 12 - n

x, 3 x^{2} = 1

5 x^{2} + 18 x = - 9

What are the solutions to the equation 6=x^2-10x ?
The solutions to the equation 6=x^2-10x are x=5+sqrt(31),x=5-sqrt(31)
Find the zeros of 6=x^2-10x
The zeros of 6=x^2-10x are x=5+sqrt(31),x=5-sqrt(31)