What are the solutions to the equation 2p^2-6p+7=0 ?

The solutions to the equation 2p^2-6p+7=0 are p= 3/2+i(sqrt(5))/2 ,p= 3/2-i(sqrt(5))/2

Find the zeros of 2p^2-6p+7=0

The zeros of 2p^2-6p+7=0 are p= 3/2+i(sqrt(5))/2 ,p= 3/2-i(sqrt(5))/2

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2 p^{2} - 6 p + 7 = 0

p = \frac{3}{2} + i \frac{5}{2}, p = \frac{3}{2} - i \frac{5}{2}

Solution steps

2 p^{2} - 6 p + 7 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

Simplify

(- 6)^{2} - 4 \cdot 2 \cdot 7 : 25 i

p_{1, 2} = \frac{- ( - 6 ) \pm 2 5 i}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- ( - 6 ) + 2 5 i}{2 \cdot 2}, p_{2} = \frac{- ( - 6 ) - 2 5 i}{2 \cdot 2}

p = \frac{- ( - 6 ) + 2 5 i}{2 \cdot 2} : \frac{3}{2} + i \frac{5}{2}

p = \frac{- ( - 6 ) - 2 5 i}{2 \cdot 2} : \frac{3}{2} - i \frac{5}{2}

The solutions to the quadratic equation are:

p = \frac{3}{2} + i \frac{5}{2}, p = \frac{3}{2} - i \frac{5}{2}

- 4 x^{2} = - 64

w^{2} - 5 w - 14 = 0

x^{2} - 13 x - 7 = 0

(\frac{2}{3}) (t^{2} - 1) = 12

\frac{x}{3} - 1 + \frac{x ^{2}}{2} = - 2 x^{2} + x - \frac{7}{6}

What are the solutions to the equation 2p^2-6p+7=0 ?
The solutions to the equation 2p^2-6p+7=0 are p= 3/2+i(sqrt(5))/2 ,p= 3/2-i(sqrt(5))/2
Find the zeros of 2p^2-6p+7=0
The zeros of 2p^2-6p+7=0 are p= 3/2+i(sqrt(5))/2 ,p= 3/2-i(sqrt(5))/2