What are the solutions to the equation x^2-25x+150=0 ?

The solutions to the equation x^2-25x+150=0 are x=15,x=10

Find the zeros of x^2-25x+150=0

The zeros of x^2-25x+150=0 are x=15,x=10

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x^{2} - 25 x + 150 = 0

x = 15, x = 10

Solution steps

x^{2} - 25 x + 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 1 \cdot 150}{2 \cdot 1}

(- 25)^{2} - 4 \cdot 1 \cdot 150 = 5

x_{1, 2} = \frac{- ( - 25 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 25 ) - 5}{2 \cdot 1}

x = \frac{- ( - 25 ) + 5}{2 \cdot 1} : 15

x = \frac{- ( - 25 ) - 5}{2 \cdot 1} : 10

The solutions to the quadratic equation are:

x = 15, x = 10

2 x^{2} + 9 x - 16 = 0

x, 1000000 x^{2} - 6200 x + 9 = 0

\frac{x}{2} (3 x - 5) = \frac{1}{2} - 3 x

a^{1} + 2 a^{2} = - 1, - 3 a^{1} + 4 a^{2} = k, 2 a^{1} - a^{2} = - 7

6 n^{2} - 18 n - 12 = 0

What are the solutions to the equation x^2-25x+150=0 ?
The solutions to the equation x^2-25x+150=0 are x=15,x=10
Find the zeros of x^2-25x+150=0
The zeros of x^2-25x+150=0 are x=15,x=10