What are the solutions to the equation completesquare 2x^2-12x+4=0 ?

The solutions to the equation completesquare 2x^2-12x+4=0 are x=sqrt(7)+3,x=-sqrt(7)+3

Find the zeros of completesquare 2x^2-12x+4=0

The zeros of completesquare 2x^2-12x+4=0 are x=sqrt(7)+3,x=-sqrt(7)+3

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2 x^{2} - 12 x + 4 = 0

x = 7 + 3, x = - 7 + 3

Decimal Notation

x = 5.64575 \dots, x = 0.35424 \dots

Solution steps

2 x^{2} - 12 x + 4 = 0

Move

4

to the right side

2 x^{2} - 12 x = - 4

Divide both sides by

2

\frac{2 x ^{2} - 12 x}{2} = \frac{- 4}{2}

x^{2} - 6 x = - 2

Rewrite in the form

(x + a)^{2} = b

(x - 3)^{2} = 7

For

the solutions are

f (x) = a, - a

Solve

x - 3 = 7 : x = 7 + 3

Solve

x - 3 = - 7 : x = - 7 + 3

The solutions to the quadratic equation are:

x = 7 + 3, x = - 7 + 3

x^{2} = 2 x - 8

4 (s - 3)^{2} = 5

x^{2} = 2 x + 6

x, 7 = 2 x^{2} - 11

2 x^{2} - 8 x + 7 = 0

What are the solutions to the equation completesquare 2x^2-12x+4=0 ?
The solutions to the equation completesquare 2x^2-12x+4=0 are x=sqrt(7)+3,x=-sqrt(7)+3
Find the zeros of completesquare 2x^2-12x+4=0
The zeros of completesquare 2x^2-12x+4=0 are x=sqrt(7)+3,x=-sqrt(7)+3