What are the solutions to the equation x(x-15)+54=0 ?

The solutions to the equation x(x-15)+54=0 are x=9,x=6

Find the zeros of x(x-15)+54=0

The zeros of x(x-15)+54=0 are x=9,x=6

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x (x - 15) + 54 = 0

x = 9, x = 6

Solution steps

x (x - 15) + 54 = 0

Expand

x (x - 15) + 54 : x^{2} - 15 x + 54

x^{2} - 15 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 54 = 3

x_{1, 2} = \frac{- ( - 15 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 3}{2 \cdot 1}

x = \frac{- ( - 15 ) + 3}{2 \cdot 1} : 9

x = \frac{- ( - 15 ) - 3}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

x = 9, x = 6

x, x^{2} + y^{2} + 2 z^{2} = 1

- \frac{1}{3} q^{2} - 10 q + 112 = \frac{1}{4} q^{2} + 5 q + 1

7 x^{2} - 8 x - 6 = 0

2 x^{2} - 8 x + 8 = 0

468 = 500 - 2 x^{2}

What are the solutions to the equation x(x-15)+54=0 ?
The solutions to the equation x(x-15)+54=0 are x=9,x=6
Find the zeros of x(x-15)+54=0
The zeros of x(x-15)+54=0 are x=9,x=6