What are the solutions to the equation (x-1)^2-49=1 ?

The solutions to the equation (x-1)^2-49=1 are x=5sqrt(2)+1,x=-5sqrt(2)+1

Find the zeros of (x-1)^2-49=1

The zeros of (x-1)^2-49=1 are x=5sqrt(2)+1,x=-5sqrt(2)+1

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(x - 1)^{2} - 49 = 1

x = 52 + 1, x = - 52 + 1

Decimal Notation

x = 8.07106 \dots, x = - 6.07106 \dots

Solution steps

(x - 1)^{2} - 49 = 1

Move

49

to the right side

(x - 1)^{2} = 50

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 50 : x = 52 + 1

Solve

x - 1 = - 50 : x = - 52 + 1

The solutions to the quadratic equation are:

x = 52 + 1, x = - 52 + 1

\frac{x}{2} + 10 = - x^{2} + 15

w^{2} + 11 w = - 28

2 z \cdot 2 z - 2 z = 12

2 x + 68 = (x + 2) (x + 4)

x^{2} + 12 x - 13 = 0

What are the solutions to the equation (x-1)^2-49=1 ?
The solutions to the equation (x-1)^2-49=1 are x=5sqrt(2)+1,x=-5sqrt(2)+1
Find the zeros of (x-1)^2-49=1
The zeros of (x-1)^2-49=1 are x=5sqrt(2)+1,x=-5sqrt(2)+1