What are the solutions to the equation 4p^2=2-5p ?

The solutions to the equation 4p^2=2-5p are p=(-5+sqrt(57))/8 ,p=(-5-sqrt(57))/8

Find the zeros of 4p^2=2-5p

The zeros of 4p^2=2-5p are p=(-5+sqrt(57))/8 ,p=(-5-sqrt(57))/8

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4 p^{2} = 2 - 5 p

p = \frac{- 5 + 57}{8}, p = \frac{- 5 - 57}{8}

Decimal Notation

p = 0.31872 \dots, p = - 1.56872 \dots

Solution steps

4 p^{2} = 2 - 5 p

Move

5 p

to the left side

4 p^{2} + 5 p = 2

Move

2

to the left side

4 p^{2} + 5 p - 2 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

5^{2} - 4 \cdot 4 (- 2) = 57

p_{1, 2} = \frac{- 5 \pm 57}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- 5 + 57}{2 \cdot 4}, p_{2} = \frac{- 5 - 57}{2 \cdot 4}

p = \frac{- 5 + 57}{2 \cdot 4} : \frac{- 5 + 57}{8}

p = \frac{- 5 - 57}{2 \cdot 4} : \frac{- 5 - 57}{8}

The solutions to the quadratic equation are:

p = \frac{- 5 + 57}{8}, p = \frac{- 5 - 57}{8}

x, 2 x^{2} + 2 y^{2} + 2 z^{2} = 8 x - 24 z + 1

2 x^{1} - x^{2} = 0

0.1 x^{2} + 0.2 x - 44 = 0

10 (x^{2} + 1) = 1

x, f (x + h) = 5 (x + h)^{2} + 8 (x + h) - 3

What are the solutions to the equation 4p^2=2-5p ?
The solutions to the equation 4p^2=2-5p are p=(-5+sqrt(57))/8 ,p=(-5-sqrt(57))/8
Find the zeros of 4p^2=2-5p
The zeros of 4p^2=2-5p are p=(-5+sqrt(57))/8 ,p=(-5-sqrt(57))/8