What are the solutions to the equation 151t-16t^2=88 ?

The solutions to the equation 151t-16t^2=88 are t=(151-sqrt(17169))/(32),t=(151+sqrt(17169))/(32)

Find the zeros of 151t-16t^2=88

The zeros of 151t-16t^2=88 are t=(151-sqrt(17169))/(32),t=(151+sqrt(17169))/(32)

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151 t - 16 t^{2} = 88

t = \frac{151 - 17169}{32}, t = \frac{151 + 17169}{32}

Decimal Notation

t = 0.62404 \dots, t = 8.81345 \dots

Solution steps

151 t - 16 t^{2} = 88

Move

88

to the left side

151 t - 16 t^{2} - 88 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 151 t - 88 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 151 \pm 15 1 ^{2} - 4 ( - 16 ) ( - 88 )}{2 ( - 16 )}

15 1^{2} - 4 (- 16) (- 88) = 17169

t_{1, 2} = \frac{- 151 \pm 17169}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 151 + 17169}{2 ( - 16 )}, t_{2} = \frac{- 151 - 17169}{2 ( - 16 )}

t = \frac{- 151 + 17169}{2 ( - 16 )} : \frac{151 - 17169}{32}

t = \frac{- 151 - 17169}{2 ( - 16 )} : \frac{151 + 17169}{32}

The solutions to the quadratic equation are:

t = \frac{151 - 17169}{32}, t = \frac{151 + 17169}{32}

\frac{2 - 3 x}{7} = x (1 - x)

x^{2} - 9 - 36 = 0

(5 x + 2) (x - 1) = 0

49 x^{2} - 225 = 0

x, x^{2} - y^{2} = 16

What are the solutions to the equation 151t-16t^2=88 ?
The solutions to the equation 151t-16t^2=88 are t=(151-sqrt(17169))/(32),t=(151+sqrt(17169))/(32)
Find the zeros of 151t-16t^2=88
The zeros of 151t-16t^2=88 are t=(151-sqrt(17169))/(32),t=(151+sqrt(17169))/(32)