What are the solutions to the equation x^2-11x+56=28 ?

The solutions to the equation x^2-11x+56=28 are x=7,x=4

Find the zeros of x^2-11x+56=28

The zeros of x^2-11x+56=28 are x=7,x=4

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x^{2} - 11 x + 56 = 28

x = 7, x = 4

Solution steps

x^{2} - 11 x + 56 = 28

Move

28

to the left side

x^{2} - 11 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 28 = 3

x_{1, 2} = \frac{- ( - 11 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 3}{2 \cdot 1}

x = \frac{- ( - 11 ) + 3}{2 \cdot 1} : 7

x = \frac{- ( - 11 ) - 3}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 7, x = 4

x, 24 x y - 3 y^{2} + 4 x^{2} - 156 = 0

x^{2} + 32 x - 64 = 0

x^{2} - 2 (m - 1) x - 2 m - 1 = 0

x^{2} - 77 x + 70 = 0

\frac{2}{3} x^{2} = 1 + 5

What are the solutions to the equation x^2-11x+56=28 ?
The solutions to the equation x^2-11x+56=28 are x=7,x=4
Find the zeros of x^2-11x+56=28
The zeros of x^2-11x+56=28 are x=7,x=4