What are the solutions to the equation 3n^2+7n-10=12 ?

The solutions to the equation 3n^2+7n-10=12 are n=(-7+sqrt(313))/6 ,n=(-7-sqrt(313))/6

Find the zeros of 3n^2+7n-10=12

The zeros of 3n^2+7n-10=12 are n=(-7+sqrt(313))/6 ,n=(-7-sqrt(313))/6

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3 n^{2} + 7 n - 10 = 12

n = \frac{- 7 + 313}{6}, n = \frac{- 7 - 313}{6}

Decimal Notation

n = 1.78196 \dots, n = - 4.11530 \dots

Solution steps

3 n^{2} + 7 n - 10 = 12

Move

12

to the left side

3 n^{2} + 7 n - 22 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 22 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 22) = 313

n_{1, 2} = \frac{- 7 \pm 313}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- 7 + 313}{2 \cdot 3}, n_{2} = \frac{- 7 - 313}{2 \cdot 3}

n = \frac{- 7 + 313}{2 \cdot 3} : \frac{- 7 + 313}{6}

n = \frac{- 7 - 313}{2 \cdot 3} : \frac{- 7 - 313}{6}

The solutions to the quadratic equation are:

n = \frac{- 7 + 313}{6}, n = \frac{- 7 - 313}{6}

100 x^{2} = 121

x^{2} + 4 x + 3 = x + 1

x^{2} + a x + 4 a^{2} = 0

16 x^{2} + 24 x - 9 = 0

x, x^{2} + 3 y^{2} = 8 + 2 x y

What are the solutions to the equation 3n^2+7n-10=12 ?
The solutions to the equation 3n^2+7n-10=12 are n=(-7+sqrt(313))/6 ,n=(-7-sqrt(313))/6
Find the zeros of 3n^2+7n-10=12
The zeros of 3n^2+7n-10=12 are n=(-7+sqrt(313))/6 ,n=(-7-sqrt(313))/6