What are the solutions to the equation (6x-5)(4-3x)=0 ?

The solutions to the equation (6x-5)(4-3x)=0 are x= 5/6 ,x= 4/3

Find the zeros of (6x-5)(4-3x)=0

The zeros of (6x-5)(4-3x)=0 are x= 5/6 ,x= 4/3

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(6 x - 5) (4 - 3 x) = 0

x = \frac{5}{6}, x = \frac{4}{3}

Decimal Notation

x = 0.83333 \dots, x = 1.33333 \dots

Solution steps

(6 x - 5) (4 - 3 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

6 x - 5 = 0 or 4 - 3 x = 0

Solve

6 x - 5 = 0 : x = \frac{5}{6}

Solve

4 - 3 x = 0 : x = \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = \frac{4}{3}

(x + 6) (x - 4) = 2 x + 12

5 x - 4 = - x^{2}

2 x^{2} + 5 x = 3

\frac{( x ) ^{2}}{2 \cdot 3 \cdot 1 0 ^{8} \cdot 4 π \cdot 1 0 ^{- 7}} = 5.01 \cdot 1 0^{3}

10 x^{2} - 2 x - 8 = 0

What are the solutions to the equation (6x-5)(4-3x)=0 ?
The solutions to the equation (6x-5)(4-3x)=0 are x= 5/6 ,x= 4/3
Find the zeros of (6x-5)(4-3x)=0
The zeros of (6x-5)(4-3x)=0 are x= 5/6 ,x= 4/3