What are the solutions to the equation (x+3)x=(6-x)2x ?

The solutions to the equation (x+3)x=(6-x)2x are x=0,x=3

Find the zeros of (x+3)x=(6-x)2x

The zeros of (x+3)x=(6-x)2x are x=0,x=3

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(x + 3) x = (6 - x) 2 x

x = 0, x = 3

Solution steps

(x + 3) x = (6 - x) \cdot 2 x

Move

(6 - x) 2 x

to the left side

(x + 3) x - (6 - x) \cdot 2 x = 0

Factor

(x + 3) x - (6 - x) \cdot 2 x : 3 x (x - 3)

3 x (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 3 = 0

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = 0, x = 3

3 x^{2} + x = - 2

1 + x + x^{2} = a (1 + x) + b \cdot (1 + x^{2}) + c \cdot (x + x^{2})

x, 16 x^{2} - 24 x y + 9 y^{2} - 30 x - 40 y = 0

2 x^{2} - 3 x + 20 = 0

x^{2} - 3 x - 7 = 3

What are the solutions to the equation (x+3)x=(6-x)2x ?
The solutions to the equation (x+3)x=(6-x)2x are x=0,x=3
Find the zeros of (x+3)x=(6-x)2x
The zeros of (x+3)x=(6-x)2x are x=0,x=3