What are the solutions to the equation y^2-8y+6=0 ?

The solutions to the equation y^2-8y+6=0 are y=4+sqrt(10),y=4-sqrt(10)

Find the zeros of y^2-8y+6=0

The zeros of y^2-8y+6=0 are y=4+sqrt(10),y=4-sqrt(10)

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y^{2} - 8 y + 6 = 0

y = 4 + 10, y = 4 - 10

Decimal Notation

y = 7.16227 \dots, y = 0.83772 \dots

Solution steps

y^{2} - 8 y + 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 6 = 210

y_{1, 2} = \frac{- ( - 8 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 2 10}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 2 10}{2 \cdot 1}

y = \frac{- ( - 8 ) + 2 10}{2 \cdot 1} : 4 + 10

y = \frac{- ( - 8 ) - 2 10}{2 \cdot 1} : 4 - 10

The solutions to the quadratic equation are:

y = 4 + 10, y = 4 - 10

14 - x^{2} = x + 2

m, (m - n)^{2} = 0

- 15 x^{2} + 200 x = 0

2 x^{2} + (- 2) x = - 2

z^{2} - 2 z - 35 = 0

What are the solutions to the equation y^2-8y+6=0 ?
The solutions to the equation y^2-8y+6=0 are y=4+sqrt(10),y=4-sqrt(10)
Find the zeros of y^2-8y+6=0
The zeros of y^2-8y+6=0 are y=4+sqrt(10),y=4-sqrt(10)