What are the solutions to the equation -32x^2+19x+17=0 ?

The solutions to the equation -32x^2+19x+17=0 are x=-(-19+sqrt(2537))/(64),x=(19+sqrt(2537))/(64)

Find the zeros of -32x^2+19x+17=0

The zeros of -32x^2+19x+17=0 are x=-(-19+sqrt(2537))/(64),x=(19+sqrt(2537))/(64)

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- 32 x^{2} + 19 x + 17 = 0

x = - \frac{- 19 + 2537}{64}, x = \frac{19 + 2537}{64}

Decimal Notation

x = - 0.49013 \dots, x = 1.08388 \dots

Solution steps

- 32 x^{2} + 19 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 ( - 32 ) \cdot 17}{2 ( - 32 )}

1 9^{2} - 4 (- 32) \cdot 17 = 2537

x_{1, 2} = \frac{- 19 \pm 2537}{2 ( - 32 )}

Separate the solutions

x_{1} = \frac{- 19 + 2537}{2 ( - 32 )}, x_{2} = \frac{- 19 - 2537}{2 ( - 32 )}

x = \frac{- 19 + 2537}{2 ( - 32 )} : - \frac{- 19 + 2537}{64}

x = \frac{- 19 - 2537}{2 ( - 32 )} : \frac{19 + 2537}{64}

The solutions to the quadratic equation are:

x = - \frac{- 19 + 2537}{64}, x = \frac{19 + 2537}{64}

x^{2} + x + 1.5 = 0

5 x (x - 1) = 2 (x^{2} - 7 x - 8)

0.1673 = 1.24 x - 7.9 x^{2}

(x + 5) (x + 2) - (x - 5) 2 = 3 (4 x - 3)

x, z = x^{2} + x y + \frac{1}{2} y^{2} - 2 x + y

What are the solutions to the equation -32x^2+19x+17=0 ?
The solutions to the equation -32x^2+19x+17=0 are x=-(-19+sqrt(2537))/(64),x=(19+sqrt(2537))/(64)
Find the zeros of -32x^2+19x+17=0
The zeros of -32x^2+19x+17=0 are x=-(-19+sqrt(2537))/(64),x=(19+sqrt(2537))/(64)