What are the solutions to the equation 1.5t+0.05t^2=0 ?

The solutions to the equation 1.5t+0.05t^2=0 are t=0,t=-30

Find the zeros of 1.5t+0.05t^2=0

The zeros of 1.5t+0.05t^2=0 are t=0,t=-30

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1.5 t + 0.05 t^{2} = 0

t = 0, t = - 30

Solution steps

1.5 t + 0.05 t^{2} = 0

Multiply both sides by

100

150 t + 5 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

5 t^{2} + 150 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 150 \pm 15 0 ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

15 0^{2} - 4 \cdot 5 \cdot 0 = 150

t_{1, 2} = \frac{- 150 \pm 150}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- 150 + 150}{2 \cdot 5}, t_{2} = \frac{- 150 - 150}{2 \cdot 5}

t = \frac{- 150 + 150}{2 \cdot 5} : 0

t = \frac{- 150 - 150}{2 \cdot 5} : - 30

The solutions to the quadratic equation are:

t = 0, t = - 30

2600 + 2 x + 0.001 x^{2} = 0

a, a^{2} + b^{2} + c^{2} = 32

8 q - q^{2} = 0

a^{2} + 8^{2} = 1 3^{2}

x, x^{2} + y^{2} + z^{2} - 6 y + 8 y = 0

What are the solutions to the equation 1.5t+0.05t^2=0 ?
The solutions to the equation 1.5t+0.05t^2=0 are t=0,t=-30
Find the zeros of 1.5t+0.05t^2=0
The zeros of 1.5t+0.05t^2=0 are t=0,t=-30