What are the solutions to the equation factor 3x^2-8x+4=0 ?

The solutions to the equation factor 3x^2-8x+4=0 are x= 2/3 ,x=2

Find the zeros of factor 3x^2-8x+4=0

The zeros of factor 3x^2-8x+4=0 are x= 2/3 ,x=2

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3 x^{2} - 8 x + 4 = 0

x = \frac{2}{3}, x = 2

Decimal Notation

x = 0.66666 \dots, x = 2

Solution steps

3 x^{2} - 8 x + 4 = 0

Factor

3 x^{2} - 8 x + 4 : (3 x - 2) (x - 2)

(3 x - 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or x - 2 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

x - 2 = 0 : x = 2

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = 2

\frac{1}{2} x^{2} + 2 x + \frac{3}{2} = 0

- \frac{1}{10} (x + 10) (x - 20)

100 x - x^{2} + 800 = 0

7 x^{2} + 4 \cdot (- 3) = 0

(x - \frac{1}{2})^{2} = x - \frac{1}{2}

What are the solutions to the equation factor 3x^2-8x+4=0 ?
The solutions to the equation factor 3x^2-8x+4=0 are x= 2/3 ,x=2
Find the zeros of factor 3x^2-8x+4=0
The zeros of factor 3x^2-8x+4=0 are x= 2/3 ,x=2