What are the solutions to the equation completesquare-2x^2+4x+3=0 ?

The solutions to the equation completesquare-2x^2+4x+3=0 are x=sqrt(5/2)+1,x=-sqrt(5/2)+1

Find the zeros of completesquare-2x^2+4x+3=0

The zeros of completesquare-2x^2+4x+3=0 are x=sqrt(5/2)+1,x=-sqrt(5/2)+1

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- 2 x^{2} + 4 x + 3 = 0

x = \frac{5}{2} + 1, x = - \frac{5}{2} + 1

Decimal Notation

x = 2.58113 \dots, x = - 0.58113 \dots

Solution steps

- 2 x^{2} + 4 x + 3 = 0

Move

3

to the right side

- 2 x^{2} + 4 x = - 3

Divide both sides by

- 2

\frac{- 2 x ^{2} + 4 x}{- 2} = \frac{- 3}{- 2}

x^{2} - 2 x = \frac{3}{2}

Rewrite in the form

(x + a)^{2} = b

(x - 1)^{2} = \frac{5}{2}

For

the solutions are

f (x) = a, - a

Solve

x - 1 = \frac{5}{2} : x = \frac{5}{2} + 1

Solve

x - 1 = - \frac{5}{2} : x = - \frac{5}{2} + 1

The solutions to the quadratic equation are:

x = \frac{5}{2} + 1, x = - \frac{5}{2} + 1

4 x^{2} - 28 x + 29 = 0

- 0.00204 x^{2} + 0.04318 x - 0.21133 = 0

x^{2} + 19 x - 66 = 0

16 + 0.5 (30 - A^{1}) = 10 + 2.5 A^{2}

12 (6 y) - 48 (y - 4) = 5 y (y - 4)

What are the solutions to the equation completesquare-2x^2+4x+3=0 ?
The solutions to the equation completesquare-2x^2+4x+3=0 are x=sqrt(5/2)+1,x=-sqrt(5/2)+1
Find the zeros of completesquare-2x^2+4x+3=0
The zeros of completesquare-2x^2+4x+3=0 are x=sqrt(5/2)+1,x=-sqrt(5/2)+1