What are the solutions to the equation 64pi=pir^2 ?

The solutions to the equation 64pi=pir^2 are r=-8,r=8

Find the zeros of 64pi=pir^2

The zeros of 64pi=pir^2 are r=-8,r=8

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64 π = π r^{2}

r = - 8, r = 8

Solution steps

64 π = π r^{2}

Move

π r^{2}

to the left side

64 π - π r^{2} = 0

Factor

64 π - π r^{2} : - π (r + 8) (r - 8)

- π (r + 8) (r - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r + 8 = 0 or r - 8 = 0

Solve

r + 8 = 0 : r = - 8

Solve

r - 8 = 0 : r = 8

The solutions to the quadratic equation are:

r = - 8, r = 8

p^{2} + 5 p - 5 = 0

x^{2} - 4 x - 30 = - 2 x + 33

0 = \frac{1}{8} \frac{x ^{2}}{3} - 8

x^{2} + 28 x + 151 = 0

175 = - 0.01 x^{2} + 200

What are the solutions to the equation 64pi=pir^2 ?
The solutions to the equation 64pi=pir^2 are r=-8,r=8
Find the zeros of 64pi=pir^2
The zeros of 64pi=pir^2 are r=-8,r=8