What are the solutions to the equation 2z^2+11z+15=0 ?

The solutions to the equation 2z^2+11z+15=0 are z=-5/2 ,z=-3

Find the zeros of 2z^2+11z+15=0

The zeros of 2z^2+11z+15=0 are z=-5/2 ,z=-3

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2 z^{2} + 11 z + 15 = 0

z = - \frac{5}{2}, z = - 3

Decimal Notation

z = - 2.5, z = - 3

Solution steps

2 z^{2} + 11 z + 15 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 \cdot 15}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 \cdot 15 = 1

z_{1, 2} = \frac{- 11 \pm 1}{2 \cdot 2}

Separate the solutions

z_{1} = \frac{- 11 + 1}{2 \cdot 2}, z_{2} = \frac{- 11 - 1}{2 \cdot 2}

z = \frac{- 11 + 1}{2 \cdot 2} : - \frac{5}{2}

z = \frac{- 11 - 1}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

z = - \frac{5}{2}, z = - 3

s^{2} + 7 s + 8 = 0

4 x^{2} - 25 + 0 = 0

2 x^{2} + 17 x - 84 = 0

6 a^{2} - 2 a - 12 = 0

5 x^{2} - 967 x + 38472 = 0

What are the solutions to the equation 2z^2+11z+15=0 ?
The solutions to the equation 2z^2+11z+15=0 are z=-5/2 ,z=-3
Find the zeros of 2z^2+11z+15=0
The zeros of 2z^2+11z+15=0 are z=-5/2 ,z=-3