What are the solutions to the equation 2x^2+7=-4x ?

The solutions to the equation 2x^2+7=-4x are x=-1+isqrt(5/2),x=-1-isqrt(5/2)

Find the zeros of 2x^2+7=-4x

The zeros of 2x^2+7=-4x are x=-1+isqrt(5/2),x=-1-isqrt(5/2)

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2 x^{2} + 7 = - 4 x

x = - 1 + i \frac{5}{2}, x = - 1 - i \frac{5}{2}

Solution steps

2 x^{2} + 7 = - 4 x

Move

4 x

to the left side

2 x^{2} + 7 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 4 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

Simplify

4^{2} - 4 \cdot 2 \cdot 7 : 210 i

x_{1, 2} = \frac{- 4 \pm 2 10 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 2 10 i}{2 \cdot 2}, x_{2} = \frac{- 4 - 2 10 i}{2 \cdot 2}

x = \frac{- 4 + 2 10 i}{2 \cdot 2} : - 1 + i \frac{5}{2}

x = \frac{- 4 - 2 10 i}{2 \cdot 2} : - 1 - i \frac{5}{2}

The solutions to the quadratic equation are:

x = - 1 + i \frac{5}{2}, x = - 1 - i \frac{5}{2}

x^{2} - 11 x + 56 = 5 x + 13

x^{2} + 13 x = 48

\frac{1}{2} x^{2} = 3 x^{2}

- x^{2} + 90 x - 130.65 = 0

(x - 1)^{2} = 20

What are the solutions to the equation 2x^2+7=-4x ?
The solutions to the equation 2x^2+7=-4x are x=-1+isqrt(5/2),x=-1-isqrt(5/2)
Find the zeros of 2x^2+7=-4x
The zeros of 2x^2+7=-4x are x=-1+isqrt(5/2),x=-1-isqrt(5/2)