What are the solutions to the equation (4t-6)^2=12 ?

The solutions to the equation (4t-6)^2=12 are t=(sqrt(3)+3)/2 ,t=(-sqrt(3)+3)/2

Find the zeros of (4t-6)^2=12

The zeros of (4t-6)^2=12 are t=(sqrt(3)+3)/2 ,t=(-sqrt(3)+3)/2

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(4 t - 6)^{2} = 12

t = \frac{3 + 3}{2}, t = \frac{- 3 + 3}{2}

Decimal Notation

t = 2.36602 \dots, t = 0.63397 \dots

Solution steps

(4 t - 6)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 t - 6 = 12 : t = \frac{3 + 3}{2}

Solve

4 t - 6 = - 12 : t = \frac{- 3 + 3}{2}

The solutions to the quadratic equation are:

t = \frac{3 + 3}{2}, t = \frac{- 3 + 3}{2}

2 x^{2} + 2 x - 12 = 0

x^{2} - 22 = - 2 x

- 6 x^{2} + 72 x - 120 = 0

- x^{2} - 9 x + 10 = 0

(x - 1)^{2} = 50

What are the solutions to the equation (4t-6)^2=12 ?
The solutions to the equation (4t-6)^2=12 are t=(sqrt(3)+3)/2 ,t=(-sqrt(3)+3)/2
Find the zeros of (4t-6)^2=12
The zeros of (4t-6)^2=12 are t=(sqrt(3)+3)/2 ,t=(-sqrt(3)+3)/2