What are the solutions to the equation 4(x-7)^2=37 ?

The solutions to the equation 4(x-7)^2=37 are x=(sqrt(37))/2+7,x=-(sqrt(37))/2+7

Find the zeros of 4(x-7)^2=37

The zeros of 4(x-7)^2=37 are x=(sqrt(37))/2+7,x=-(sqrt(37))/2+7

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4 (x - 7)^{2} = 37

x = \frac{37}{2} + 7, x = - \frac{37}{2} + 7

Decimal Notation

x = 10.04138 \dots, x = 3.95861 \dots

Solution steps

4 (x - 7)^{2} = 37

Divide both sides by

4

(x - 7)^{2} = \frac{37}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 7 = \frac{37}{4} : x = \frac{37}{2} + 7

Solve

x - 7 = - \frac{37}{4} : x = - \frac{37}{2} + 7

The solutions to the quadratic equation are:

x = \frac{37}{2} + 7, x = - \frac{37}{2} + 7

x, x^{2} + 11 x + \frac{121}{4} = \frac{125}{4}

0.036 s^{2} + 1200 s + 30000000 = 0

v^{2} - 5 = 8 - 2 v^{2}

3 z^{2} - 42 = 0

(4 x - 1) (8 x + 1) = 0

What are the solutions to the equation 4(x-7)^2=37 ?
The solutions to the equation 4(x-7)^2=37 are x=(sqrt(37))/2+7,x=-(sqrt(37))/2+7
Find the zeros of 4(x-7)^2=37
The zeros of 4(x-7)^2=37 are x=(sqrt(37))/2+7,x=-(sqrt(37))/2+7