What are the solutions to the equation factor 6x^2+4x+1=9x ?

The solutions to the equation factor 6x^2+4x+1=9x are x= 1/3 ,x= 1/2

Find the zeros of factor 6x^2+4x+1=9x

The zeros of factor 6x^2+4x+1=9x are x= 1/3 ,x= 1/2

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6 x^{2} + 4 x + 1 = 9 x

x = \frac{1}{3}, x = \frac{1}{2}

Decimal Notation

x = 0.33333 \dots, x = 0.5

Solution steps

6 x^{2} + 4 x + 1 = 9 x

Move

9 x

to the left side

6 x^{2} - 5 x + 1 = 0

Factor

6 x^{2} - 5 x + 1 : (3 x - 1) (2 x - 1)

(3 x - 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or 2 x - 1 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = \frac{1}{2}

a^{2} + 3 6^{2} = 3 9^{2}

y, x^{2} + y^{2} = 2 y

x^{2} + 10 x + 25 = 14

16 x^{2} - 5 x + 1 = 0

t, r (t) = 4 t - 3 t^{2} + 5

What are the solutions to the equation factor 6x^2+4x+1=9x ?
The solutions to the equation factor 6x^2+4x+1=9x are x= 1/3 ,x= 1/2
Find the zeros of factor 6x^2+4x+1=9x
The zeros of factor 6x^2+4x+1=9x are x= 1/3 ,x= 1/2