What are the solutions to the equation solvefor x,f=k-5k+1x^2-20 ?

The solutions to the equation solvefor x,f=k-5k+1x^2-20 are x=sqrt(f+4k+20),x=-sqrt(f+4k+20)

Find the zeros of solvefor x,f=k-5k+1x^2-20

The zeros of solvefor x,f=k-5k+1x^2-20 are x=sqrt(f+4k+20),x=-sqrt(f+4k+20)

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solve for

x, f = k - 5 k + 1 x^{2} - 20

x = f + 4 k + 20, x = - f + 4 k + 20

Solution steps

f = k - 5 k + 1 \cdot x^{2} - 20

Switch sides

k - 5 k + 1 \cdot x^{2} - 20 = f

Move

k

to the right side

- 5 k + 1 \cdot x^{2} - 20 = f - k

Move

5 k

to the right side

1 \cdot x^{2} - 20 = f + 4 k

Move

20

to the right side

1 \cdot x^{2} = f + 4 k + 20

Multiply:

1 \cdot x^{2} = x^{2}

x^{2} = f + 4 k + 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = f + 4 k + 20, x = - f + 4 k + 20

6 x^{2} + 24 x - 30 = 810

x^{2} - 15 x = 11 - 5 x

c^{2} = 6^{2} + 5^{2}

x^{2} - 8 = 17

(4 x + 2) (3 x - 7) = 0

What are the solutions to the equation solvefor x,f=k-5k+1x^2-20 ?
The solutions to the equation solvefor x,f=k-5k+1x^2-20 are x=sqrt(f+4k+20),x=-sqrt(f+4k+20)
Find the zeros of solvefor x,f=k-5k+1x^2-20
The zeros of solvefor x,f=k-5k+1x^2-20 are x=sqrt(f+4k+20),x=-sqrt(f+4k+20)