What are the solutions to the equation 6=a^2+8 ?

The solutions to the equation 6=a^2+8 are a=sqrt(2)i,a=-sqrt(2)i

Find the zeros of 6=a^2+8

The zeros of 6=a^2+8 are a=sqrt(2)i,a=-sqrt(2)i

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6 = a^{2} + 8

a = 2 i, a = - 2 i

Solution steps

6 = a^{2} + 8

Switch sides

a^{2} + 8 = 6

Move

8

to the right side

a^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = - 2, a = - - 2

- 2 = 2 i

- - 2 = - 2 i

a = 2 i, a = - 2 i

(x + 5) (2 x - 3) = 9

2 x^{2} + 7 x - 18 = x^{2}

2 0^{2} + 2 \cdot 32.2 = v^{2} + 50 (5 - 2)^{2}

x, 3.1396 (1 - x^{2}) = (π) (x)^{2}

- t^{2} + 27 t + 3 = - 2 t^{2} + 25 t + 27

What are the solutions to the equation 6=a^2+8 ?
The solutions to the equation 6=a^2+8 are a=sqrt(2)i,a=-sqrt(2)i
Find the zeros of 6=a^2+8
The zeros of 6=a^2+8 are a=sqrt(2)i,a=-sqrt(2)i