What are the solutions to the equation 14=2x^2-12x ?

The solutions to the equation 14=2x^2-12x are x=7,x=-1

Find the zeros of 14=2x^2-12x

The zeros of 14=2x^2-12x are x=7,x=-1

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14 = 2 x^{2} - 12 x

x = 7, x = - 1

Solution steps

14 = 2 x^{2} - 12 x

Switch sides

2 x^{2} - 12 x = 14

Move

14

to the left side

2 x^{2} - 12 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 (- 14) = 16

x_{1, 2} = \frac{- ( - 12 ) \pm 16}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 16}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 16}{2 \cdot 2}

x = \frac{- ( - 12 ) + 16}{2 \cdot 2} : 7

x = \frac{- ( - 12 ) - 16}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 7, x = - 1

- \frac{2}{3} \cdot \frac{1}{2} + \frac{2}{3} \cdot \frac{1}{2} \cdot \frac{1}{5}

3 ∣ 2 x - 5 ∣ \geq 8

\frac{( - 4 x ^{5} y ) ^{2}}{48 x ^{2} y ^{2}}

(x + 4)^{2} - 25

\frac{3}{4} x + 4 = 22

What are the solutions to the equation 14=2x^2-12x ?
The solutions to the equation 14=2x^2-12x are x=7,x=-1
Find the zeros of 14=2x^2-12x
The zeros of 14=2x^2-12x are x=7,x=-1