What are the solutions to the equation -6x(x-7)=4(x+7)+4x ?

The solutions to the equation -6x(x-7)=4(x+7)+4x are x=1,x= 14/3

Find the zeros of -6x(x-7)=4(x+7)+4x

The zeros of -6x(x-7)=4(x+7)+4x are x=1,x= 14/3

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- 6 x (x - 7) = 4 (x + 7) + 4 x

x = 1, x = \frac{14}{3}

Decimal Notation

x = 1, x = 4.66666 \dots

Solution steps

- 6 x (x - 7) = 4 (x + 7) + 4 x

Expand

- 6 x (x - 7) : - 6 x^{2} + 42 x

Expand

4 (x + 7) + 4 x : 8 x + 28

- 6 x^{2} + 42 x = 8 x + 28

Move

28

to the left side

- 6 x^{2} + 42 x - 28 = 8 x

Move

8 x

to the left side

- 6 x^{2} + 34 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 34 \pm 3 4 ^{2} - 4 ( - 6 ) ( - 28 )}{2 ( - 6 )}

3 4^{2} - 4 (- 6) (- 28) = 22

x_{1, 2} = \frac{- 34 \pm 22}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 34 + 22}{2 ( - 6 )}, x_{2} = \frac{- 34 - 22}{2 ( - 6 )}

x = \frac{- 34 + 22}{2 ( - 6 )} : 1

x = \frac{- 34 - 22}{2 ( - 6 )} : \frac{14}{3}

The solutions to the quadratic equation are:

x = 1, x = \frac{14}{3}

5 t = 2 t^{2}

0.44 x^{2} - 1.06 x + 0.786 = 0

x, f = {0.25 x^{2}}

x, 2 x^{2} - 8 x y + 8 y^{2} + x - 5 y - 4 = 0

3 x^{2} - 40 x + 150 = 73

What are the solutions to the equation -6x(x-7)=4(x+7)+4x ?
The solutions to the equation -6x(x-7)=4(x+7)+4x are x=1,x= 14/3
Find the zeros of -6x(x-7)=4(x+7)+4x
The zeros of -6x(x-7)=4(x+7)+4x are x=1,x= 14/3