What are the solutions to the equation 2x^2-18x=-28 ?

The solutions to the equation 2x^2-18x=-28 are x=7,x=2

Find the zeros of 2x^2-18x=-28

The zeros of 2x^2-18x=-28 are x=7,x=2

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2 x^{2} - 18 x = - 28

x = 7, x = 2

Solution steps

2 x^{2} - 18 x = - 28

Move

28

to the left side

2 x^{2} - 18 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 2 \cdot 28}{2 \cdot 2}

(- 18)^{2} - 4 \cdot 2 \cdot 28 = 10

x_{1, 2} = \frac{- ( - 18 ) \pm 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 10}{2 \cdot 2}, x_{2} = \frac{- ( - 18 ) - 10}{2 \cdot 2}

x = \frac{- ( - 18 ) + 10}{2 \cdot 2} : 7

x = \frac{- ( - 18 ) - 10}{2 \cdot 2} : 2

The solutions to the quadratic equation are:

x = 7, x = 2

5 x^{2} = 40 x

x = 0.55 \cdot (6.71 - x \cdot 0.75)^{2}

x, 4 x^{2} = 0

x^{2} + 10 x - 3 = 0

6 x^{2} + 5 x + 6 = 0

What are the solutions to the equation 2x^2-18x=-28 ?
The solutions to the equation 2x^2-18x=-28 are x=7,x=2
Find the zeros of 2x^2-18x=-28
The zeros of 2x^2-18x=-28 are x=7,x=2