What are the solutions to the equation completesquare 2x^2+3x-3=0 ?

The solutions to the equation completesquare 2x^2+3x-3=0 are x=(sqrt(33)-3)/4 ,x=(-sqrt(33)-3)/4

Find the zeros of completesquare 2x^2+3x-3=0

The zeros of completesquare 2x^2+3x-3=0 are x=(sqrt(33)-3)/4 ,x=(-sqrt(33)-3)/4

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2 x^{2} + 3 x - 3 = 0

x = \frac{33 - 3}{4}, x = \frac{- 33 - 3}{4}

Decimal Notation

x = 0.68614 \dots, x = - 2.18614 \dots

Solution steps

2 x^{2} + 3 x - 3 = 0

Move

3

to the right side

2 x^{2} + 3 x = 3

Divide both sides by

2

\frac{2 x ^{2} + 3 x}{2} = \frac{3}{2}

x^{2} + \frac{3 x}{2} = \frac{3}{2}

Rewrite in the form

(x + a)^{2} = b

(x + \frac{3}{4})^{2} = \frac{33}{16}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{3}{4} = \frac{33}{16} : x = \frac{33 - 3}{4}

Solve

x + \frac{3}{4} = - \frac{33}{16} : x = \frac{- 33 - 3}{4}

The solutions to the quadratic equation are:

x = \frac{33 - 3}{4}, x = \frac{- 33 - 3}{4}

x, (m - 2) x^{2} + (n - 1) x + (p - 3) = 0

5 r^{2} - 6 r + 1 = 0

X^{2} - 3 X + 1 = 0

3 x^{2} - 3 x + 0.54 = 0

r^{2} - \frac{2}{3} r = 0

What are the solutions to the equation completesquare 2x^2+3x-3=0 ?
The solutions to the equation completesquare 2x^2+3x-3=0 are x=(sqrt(33)-3)/4 ,x=(-sqrt(33)-3)/4
Find the zeros of completesquare 2x^2+3x-3=0
The zeros of completesquare 2x^2+3x-3=0 are x=(sqrt(33)-3)/4 ,x=(-sqrt(33)-3)/4