What are the solutions to the equation -2x^2+9x-4=0 ?

The solutions to the equation -2x^2+9x-4=0 are x= 1/2 ,x=4

Find the zeros of -2x^2+9x-4=0

The zeros of -2x^2+9x-4=0 are x= 1/2 ,x=4

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- 2 x^{2} + 9 x - 4 = 0

x = \frac{1}{2}, x = 4

Decimal Notation

x = 0.5, x = 4

Solution steps

- 2 x^{2} + 9 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 2 ) ( - 4 )}{2 ( - 2 )}

9^{2} - 4 (- 2) (- 4) = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 9 + 7}{2 ( - 2 )}, x_{2} = \frac{- 9 - 7}{2 ( - 2 )}

x = \frac{- 9 + 7}{2 ( - 2 )} : \frac{1}{2}

x = \frac{- 9 - 7}{2 ( - 2 )} : 4

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 4

\frac{w}{50} = - 3

45 b^{2} + 180 b + 100

2 x - 10 = - 26

3 (x + 1) + 4 x + 3 = 34

x^{2} + 2 x + 2 < 0

What are the solutions to the equation -2x^2+9x-4=0 ?
The solutions to the equation -2x^2+9x-4=0 are x= 1/2 ,x=4
Find the zeros of -2x^2+9x-4=0
The zeros of -2x^2+9x-4=0 are x= 1/2 ,x=4