What are the solutions to the equation t^2-6t-4=0 ?

The solutions to the equation t^2-6t-4=0 are t=3+sqrt(13),t=3-sqrt(13)

Find the zeros of t^2-6t-4=0

The zeros of t^2-6t-4=0 are t=3+sqrt(13),t=3-sqrt(13)

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t^{2} - 6 t - 4 = 0

t = 3 + 13, t = 3 - 13

Decimal Notation

t = 6.60555 \dots, t = - 0.60555 \dots

Solution steps

t^{2} - 6 t - 4 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 4) = 213

t_{1, 2} = \frac{- ( - 6 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 6 ) + 2 13}{2 \cdot 1}, t_{2} = \frac{- ( - 6 ) - 2 13}{2 \cdot 1}

t = \frac{- ( - 6 ) + 2 13}{2 \cdot 1} : 3 + 13

t = \frac{- ( - 6 ) - 2 13}{2 \cdot 1} : 3 - 13

The solutions to the quadratic equation are:

t = 3 + 13, t = 3 - 13

3 = x (x + 2)

4 a^{2} + 20 a^{2} + 9 = 0

x^{2} - 12 + 32 = 0

36 x^{2} - 24 x + 85 = 0

3 n^{2} - 4 n = 5

What are the solutions to the equation t^2-6t-4=0 ?
The solutions to the equation t^2-6t-4=0 are t=3+sqrt(13),t=3-sqrt(13)
Find the zeros of t^2-6t-4=0
The zeros of t^2-6t-4=0 are t=3+sqrt(13),t=3-sqrt(13)