What are the solutions to the equation x=8*10^{-3}*(1-250x)^2 ?

The solutions to the equation x=8*10^{-3}*(1-250x)^2 are x= 1/125 ,x= 1/500

Find the zeros of x=8*10^{-3}*(1-250x)^2

The zeros of x=8*10^{-3}*(1-250x)^2 are x= 1/125 ,x= 1/500

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x = 8 \cdot 1 0^{- 3} \cdot (1 - 250 x)^{2}

x = \frac{1}{125}, x = \frac{1}{500}

Decimal Notation

x = 0.008, x = 0.002

Solution steps

x = 8 \cdot 1 0^{- 3} (1 - 250 x)^{2}

Expand

8 \cdot 1 0^{- 3} (1 - 250 x)^{2} : \frac{1}{125} - 4 x + 500 x^{2}

x = \frac{1}{125} - 4 x + 500 x^{2}

Switch sides

\frac{1}{125} - 4 x + 500 x^{2} = x

Move

x

to the left side

500 x^{2} - 5 x + \frac{1}{125} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 500 \cdot \frac{1}{125}}{2 \cdot 500}

(- 5)^{2} - 4 \cdot 500 \cdot \frac{1}{125} = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 500}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 500}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 500}

x = \frac{- ( - 5 ) + 3}{2 \cdot 500} : \frac{1}{125}

x = \frac{- ( - 5 ) - 3}{2 \cdot 500} : \frac{1}{500}

The solutions to the quadratic equation are:

x = \frac{1}{125}, x = \frac{1}{500}

6 x^{2} + 13 x - 5 = (2 x + 5)

(7 - 603 x) (1 - 341 x) - (1 + 9 x)^{2} = 0

1 3^{2} - 10 r - 10 = 10 r^{2} - 6

x, 2 y^{2} - 2 x y + 4 y = 4 x y - x^{2} + 4 x

1 2^{2} + x^{2} = 5^{2}

What are the solutions to the equation x=8*10^{-3}*(1-250x)^2 ?
The solutions to the equation x=8*10^{-3}*(1-250x)^2 are x= 1/125 ,x= 1/500
Find the zeros of x=8*10^{-3}*(1-250x)^2
The zeros of x=8*10^{-3}*(1-250x)^2 are x= 1/125 ,x= 1/500