What are the solutions to the equation p^2-12p+9=0 ?

The solutions to the equation p^2-12p+9=0 are p=3(2+sqrt(3)),p=3(2-sqrt(3))

Find the zeros of p^2-12p+9=0

The zeros of p^2-12p+9=0 are p=3(2+sqrt(3)),p=3(2-sqrt(3))

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p^{2} - 12 p + 9 = 0

p = 3 (2 + 3), p = 3 (2 - 3)

Decimal Notation

p = 11.19615 \dots, p = 0.80384 \dots

Solution steps

p^{2} - 12 p + 9 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 9 = 63

p_{1, 2} = \frac{- ( - 12 ) \pm 6 3}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 12 ) + 6 3}{2 \cdot 1}, p_{2} = \frac{- ( - 12 ) - 6 3}{2 \cdot 1}

p = \frac{- ( - 12 ) + 6 3}{2 \cdot 1} : 3 (2 + 3)

p = \frac{- ( - 12 ) - 6 3}{2 \cdot 1} : 3 (2 - 3)

The solutions to the quadratic equation are:

p = 3 (2 + 3), p = 3 (2 - 3)

x, z = 5 y x^{2}

2200 - x^{2} = 400 + x^{2}

2 - \frac{x ^{2}}{2} = 0

x^{2} + 36 = - 12 x

\frac{8}{7} x + \frac{32}{7} = x^{2} + \frac{15}{7} x - \frac{52}{7}

What are the solutions to the equation p^2-12p+9=0 ?
The solutions to the equation p^2-12p+9=0 are p=3(2+sqrt(3)),p=3(2-sqrt(3))
Find the zeros of p^2-12p+9=0
The zeros of p^2-12p+9=0 are p=3(2+sqrt(3)),p=3(2-sqrt(3))