What are the solutions to the equation solvefor x,(x+7)(x-9)=25 ?

The solutions to the equation solvefor x,(x+7)(x-9)=25 are x=1+sqrt(89),x=1-sqrt(89)

Find the zeros of solvefor x,(x+7)(x-9)=25

The zeros of solvefor x,(x+7)(x-9)=25 are x=1+sqrt(89),x=1-sqrt(89)

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x, (x + 7) (x - 9) = 25

x = 1 + 89, x = 1 - 89

Decimal Notation

x = 10.43398 \dots, x = - 8.43398 \dots

Solution steps

(x + 7) (x - 9) = 25

Expand

(x + 7) (x - 9) : x^{2} - 2 x - 63

x^{2} - 2 x - 63 = 25

Move

25

to the left side

x^{2} - 2 x - 88 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 88 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 88) = 289

x_{1, 2} = \frac{- ( - 2 ) \pm 2 89}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 89}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 89}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 89}{2 \cdot 1} : 1 + 89

x = \frac{- ( - 2 ) - 2 89}{2 \cdot 1} : 1 - 89

The solutions to the quadratic equation are:

x = 1 + 89, x = 1 - 89

4 0^{2} + 19 8^{2} = c^{2}

15 x^{2} + 160 x - 9600 = 0

1665 = 18500 (0.25 - r^{2})

- 3 x^{2} + 24 x + 6 = 0

e^{2} = x^{2}

What are the solutions to the equation solvefor x,(x+7)(x-9)=25 ?
The solutions to the equation solvefor x,(x+7)(x-9)=25 are x=1+sqrt(89),x=1-sqrt(89)
Find the zeros of solvefor x,(x+7)(x-9)=25
The zeros of solvefor x,(x+7)(x-9)=25 are x=1+sqrt(89),x=1-sqrt(89)