What are the solutions to the equation 5x^2+20=-25 ?

The solutions to the equation 5x^2+20=-25 are x=3i,x=-3i

Find the zeros of 5x^2+20=-25

The zeros of 5x^2+20=-25 are x=3i,x=-3i

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5 x^{2} + 20 = - 25

x = 3 i, x = - 3 i

Solution steps

5 x^{2} + 20 = - 25

Move

20

to the right side

5 x^{2} = - 45

Divide both sides by

5

x^{2} = - 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 9, x = - - 9

- 9 = 3 i

- - 9 = - 3 i

x = 3 i, x = - 3 i

- 16 t^{2} + 64 t + 80 = 0

p^{2} + \frac{1}{16} = 0

30 x - 0.1 x^{2} = 1890

x, y^{2} z p + x^{2} z q = x y^{2}

3 x^{2} + 12 = 63

What are the solutions to the equation 5x^2+20=-25 ?
The solutions to the equation 5x^2+20=-25 are x=3i,x=-3i
Find the zeros of 5x^2+20=-25
The zeros of 5x^2+20=-25 are x=3i,x=-3i