What are the solutions to the equation 3x^2-2x=4x+x^2 ?

The solutions to the equation 3x^2-2x=4x+x^2 are x=3,x=0

Find the zeros of 3x^2-2x=4x+x^2

The zeros of 3x^2-2x=4x+x^2 are x=3,x=0

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3 x^{2} - 2 x = 4 x + x^{2}

x = 3, x = 0

Solution steps

3 x^{2} - 2 x = 4 x + x^{2}

Move

x^{2}

to the left side

2 x^{2} - 2 x = 4 x

Move

4 x

to the left side

2 x^{2} - 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 \cdot 0 = 6

x_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 2}

x = \frac{- ( - 6 ) + 6}{2 \cdot 2} : 3

x = \frac{- ( - 6 ) - 6}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

x^{2} - 10 x + 25 - 9 = 0

39 y^{2} + 48 y + 9 = 0

s^{2} + 1.33 \cdot s + 4.34 = 0

x (2 x - 1) = 3 x - 5 (x + 2)

x, (2 x - 4)^{2} + 3 = 2 (x^{2} + 3) - 4

What are the solutions to the equation 3x^2-2x=4x+x^2 ?
The solutions to the equation 3x^2-2x=4x+x^2 are x=3,x=0
Find the zeros of 3x^2-2x=4x+x^2
The zeros of 3x^2-2x=4x+x^2 are x=3,x=0