What are the solutions to the equation x^2-24x+72=0 ?

The solutions to the equation x^2-24x+72=0 are x=6(2+sqrt(2)),x=6(2-sqrt(2))

Find the zeros of x^2-24x+72=0

The zeros of x^2-24x+72=0 are x=6(2+sqrt(2)),x=6(2-sqrt(2))

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x^{2} - 24 x + 72 = 0

x = 6 (2 + 2), x = 6 (2 - 2)

Decimal Notation

x = 20.48528 \dots, x = 3.51471 \dots

Solution steps

x^{2} - 24 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot 72}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot 72 = 122

x_{1, 2} = \frac{- ( - 24 ) \pm 12 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12 2}{2 \cdot 1}, x_{2} = \frac{- ( - 24 ) - 12 2}{2 \cdot 1}

x = \frac{- ( - 24 ) + 12 2}{2 \cdot 1} : 6 (2 + 2)

x = \frac{- ( - 24 ) - 12 2}{2 \cdot 1} : 6 (2 - 2)

The solutions to the quadratic equation are:

x = 6 (2 + 2), x = 6 (2 - 2)

m^{2} = 100

p^{2} - 6 p + 9 = 0

x (x + 1) = 1.675 \cdot 1 0^{29}

3 x = x^{2} - 18

2 x^{2} = - 6 x - 1

What are the solutions to the equation x^2-24x+72=0 ?
The solutions to the equation x^2-24x+72=0 are x=6(2+sqrt(2)),x=6(2-sqrt(2))
Find the zeros of x^2-24x+72=0
The zeros of x^2-24x+72=0 are x=6(2+sqrt(2)),x=6(2-sqrt(2))