What are the solutions to the equation quadraticformula 2x^2+6x+3=0 ?

The solutions to the equation quadraticformula 2x^2+6x+3=0 are x=(-3+sqrt(3))/2 ,x=-(3+sqrt(3))/2

Find the zeros of quadraticformula 2x^2+6x+3=0

The zeros of quadraticformula 2x^2+6x+3=0 are x=(-3+sqrt(3))/2 ,x=-(3+sqrt(3))/2

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2 x^{2} + 6 x + 3 = 0

x = \frac{- 3 + 3}{2}, x = - \frac{3 + 3}{2}

Decimal Notation

x = - 0.63397 \dots, x = - 2.36602 \dots

Solution steps

2 x^{2} + 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

6^{2} - 4 \cdot 2 \cdot 3 = 23

x_{1, 2} = \frac{- 6 \pm 2 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 2 3}{2 \cdot 2}, x_{2} = \frac{- 6 - 2 3}{2 \cdot 2}

x = \frac{- 6 + 2 3}{2 \cdot 2} : \frac{- 3 + 3}{2}

x = \frac{- 6 - 2 3}{2 \cdot 2} : - \frac{3 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 3}{2}, x = - \frac{3 + 3}{2}

x^{2} + 445 x - 2225 = 0

x, 4 x^{2} + 4 y^{2} = z^{2}

- 3 x^{2} - 3 x + 10

a^{2} = 3^{2} + 4^{2}

m (m - 1) + 11 m + 5 = 0

What are the solutions to the equation quadraticformula 2x^2+6x+3=0 ?
The solutions to the equation quadraticformula 2x^2+6x+3=0 are x=(-3+sqrt(3))/2 ,x=-(3+sqrt(3))/2
Find the zeros of quadraticformula 2x^2+6x+3=0
The zeros of quadraticformula 2x^2+6x+3=0 are x=(-3+sqrt(3))/2 ,x=-(3+sqrt(3))/2