What are the solutions to the equation 3x^2-6=23x+2 ?

The solutions to the equation 3x^2-6=23x+2 are x=8,x=-1/3

Find the zeros of 3x^2-6=23x+2

The zeros of 3x^2-6=23x+2 are x=8,x=-1/3

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3 x^{2} - 6 = 23 x + 2

x = 8, x = - \frac{1}{3}

Decimal Notation

x = 8, x = - 0.33333 \dots

Solution steps

3 x^{2} - 6 = 23 x + 2

Move

2

to the left side

3 x^{2} - 8 = 23 x

Move

23 x

to the left side

3 x^{2} - 8 - 23 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 23 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

(- 23)^{2} - 4 \cdot 3 (- 8) = 25

x_{1, 2} = \frac{- ( - 23 ) \pm 25}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 25}{2 \cdot 3}, x_{2} = \frac{- ( - 23 ) - 25}{2 \cdot 3}

x = \frac{- ( - 23 ) + 25}{2 \cdot 3} : 8

x = \frac{- ( - 23 ) - 25}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = 8, x = - \frac{1}{3}

3 (x + 7) < 7 (x + 2)

(\frac{14 x}{15 y}) (\frac{25 y}{24})

\frac{( a ^{2} - b ^{(2)} )}{( a + b )} - (a + b)^{2} + 2 (a^{2} + ab)

x^{3} + 4 x^{2} - 19 x + 14

2 \leq - 1 t

What are the solutions to the equation 3x^2-6=23x+2 ?
The solutions to the equation 3x^2-6=23x+2 are x=8,x=-1/3
Find the zeros of 3x^2-6=23x+2
The zeros of 3x^2-6=23x+2 are x=8,x=-1/3