What are the solutions to the equation x^2+5x+9=-3x-3 ?

The solutions to the equation x^2+5x+9=-3x-3 are x=-2,x=-6

Find the zeros of x^2+5x+9=-3x-3

The zeros of x^2+5x+9=-3x-3 are x=-2,x=-6

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x^{2} + 5 x + 9 = - 3 x - 3

x = - 2, x = - 6

Solution steps

x^{2} + 5 x + 9 = - 3 x - 3

Move

3

to the left side

x^{2} + 5 x + 12 = - 3 x

Move

3 x

to the left side

x^{2} + 8 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 12 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 \cdot 1}, x_{2} = \frac{- 8 - 4}{2 \cdot 1}

x = \frac{- 8 + 4}{2 \cdot 1} : - 2

x = \frac{- 8 - 4}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 2, x = - 6

t^{2} - 16 t = - 63

n (n - 3) = 40

y, y^{2} + a^{2} = (a + y) 2 - a (a + 1)

a = (2 x + 1) 2 - (2 x - 1) 2 - (2 - x) (2 + x) - (x + 1) 2 + 5

x^{2} + x + 100.25 = 0

What are the solutions to the equation x^2+5x+9=-3x-3 ?
The solutions to the equation x^2+5x+9=-3x-3 are x=-2,x=-6
Find the zeros of x^2+5x+9=-3x-3
The zeros of x^2+5x+9=-3x-3 are x=-2,x=-6