What are the solutions to the equation (7+X)^2+(7-X)^2=130 ?

The solutions to the equation (7+X)^2+(7-X)^2=130 are X=4,X=-4

Find the zeros of (7+X)^2+(7-X)^2=130

The zeros of (7+X)^2+(7-X)^2=130 are X=4,X=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(7 + X)^{2} + (7 - X)^{2} = 130

X = 4, X = - 4

Solution steps

(7 + X)^{2} + (7 - X)^{2} = 130

Expand

(7 + X)^{2} + (7 - X)^{2} : 2 X^{2} + 98

2 X^{2} + 98 = 130

Move

130

to the left side

2 X^{2} - 32 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 ( - 32 )}{2 \cdot 2}

0^{2} - 4 \cdot 2 (- 32) = 16

X_{1, 2} = \frac{- 0 \pm 16}{2 \cdot 2}

Separate the solutions

X_{1} = \frac{- 0 + 16}{2 \cdot 2}, X_{2} = \frac{- 0 - 16}{2 \cdot 2}

X = \frac{- 0 + 16}{2 \cdot 2} : 4

X = \frac{- 0 - 16}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

X = 4, X = - 4

- x^{2} + 4 x + 36 = 0

4 x^{2} - 17 x + 11 = 0

x, x^{2} + y^{2} + 6 x - 10 y + 35 = 0

900 a = 100 a^{2}

0.1 t - 30.1 tt = 5

What are the solutions to the equation (7+X)^2+(7-X)^2=130 ?
The solutions to the equation (7+X)^2+(7-X)^2=130 are X=4,X=-4
Find the zeros of (7+X)^2+(7-X)^2=130
The zeros of (7+X)^2+(7-X)^2=130 are X=4,X=-4