What are the solutions to the equation 100x^2+81=0 ?

The solutions to the equation 100x^2+81=0 are x= 9/10 i,x=-9/10 i

Find the zeros of 100x^2+81=0

The zeros of 100x^2+81=0 are x= 9/10 i,x=-9/10 i

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100 x^{2} + 81 = 0

x = \frac{9}{10} i, x = - \frac{9}{10} i

Solution steps

100 x^{2} + 81 = 0

Move

81

to the right side

100 x^{2} = - 81

Divide both sides by

100

x^{2} = - \frac{81}{100}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{81}{100}, x = - - \frac{81}{100}

- \frac{81}{100} = \frac{9}{10} i

- - \frac{81}{100} = - \frac{9}{10} i

x = \frac{9}{10} i, x = - \frac{9}{10} i

- 4 x^{2} + 2 a x + 2 a^{2} = 0

x^{2} = (2 x + 13)^{2} - (x - 13)^{2}

(2 x - 3)^{2} = (x + 1) (2 x - 3)

2 x^{2} + 3 x + 1 = 0

3 y^{2} + 6 = 11 y

What are the solutions to the equation 100x^2+81=0 ?
The solutions to the equation 100x^2+81=0 are x= 9/10 i,x=-9/10 i
Find the zeros of 100x^2+81=0
The zeros of 100x^2+81=0 are x= 9/10 i,x=-9/10 i