What are the solutions to the equation x(x+7)=690 ?

The solutions to the equation x(x+7)=690 are x=23,x=-30

Find the zeros of x(x+7)=690

The zeros of x(x+7)=690 are x=23,x=-30

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x (x + 7) = 690

x = 23, x = - 30

Solution steps

x (x + 7) = 690

Expand

x (x + 7) : x^{2} + 7 x

x^{2} + 7 x = 690

Move

690

to the left side

x^{2} + 7 x - 690 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 690 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 690) = 53

x_{1, 2} = \frac{- 7 \pm 53}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 53}{2 \cdot 1}, x_{2} = \frac{- 7 - 53}{2 \cdot 1}

x = \frac{- 7 + 53}{2 \cdot 1} : 23

x = \frac{- 7 - 53}{2 \cdot 1} : - 30

The solutions to the quadratic equation are:

x = 23, x = - 30

2 x (3 x + 5) = - 1 + 4 x

\frac{1}{2} x^{2} - 4 x + 3

x^{2} + a^{2} x^{2} - 4 x a^{2} + 4 a^{2} = 1

- 11 x + 5 + 2 x^{2} = 0

7 - 4 (y + 3) - (y + 3)^{2} = 0

What are the solutions to the equation x(x+7)=690 ?
The solutions to the equation x(x+7)=690 are x=23,x=-30
Find the zeros of x(x+7)=690
The zeros of x(x+7)=690 are x=23,x=-30