What are the solutions to the equation -3x^2+9x-2=0 ?

The solutions to the equation -3x^2+9x-2=0 are x=(9-sqrt(57))/6 ,x=(9+sqrt(57))/6

Find the zeros of -3x^2+9x-2=0

The zeros of -3x^2+9x-2=0 are x=(9-sqrt(57))/6 ,x=(9+sqrt(57))/6

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- 3 x^{2} + 9 x - 2 = 0

x = \frac{9 - 57}{6}, x = \frac{9 + 57}{6}

Decimal Notation

x = 0.24169 \dots, x = 2.75830 \dots

Solution steps

- 3 x^{2} + 9 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 3 ) ( - 2 )}{2 ( - 3 )}

9^{2} - 4 (- 3) (- 2) = 57

x_{1, 2} = \frac{- 9 \pm 57}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 9 + 57}{2 ( - 3 )}, x_{2} = \frac{- 9 - 57}{2 ( - 3 )}

x = \frac{- 9 + 57}{2 ( - 3 )} : \frac{9 - 57}{6}

x = \frac{- 9 - 57}{2 ( - 3 )} : \frac{9 + 57}{6}

The solutions to the quadratic equation are:

x = \frac{9 - 57}{6}, x = \frac{9 + 57}{6}

- 4 x^{2} + 3 = 5 x^{2} - 6 x - 4

z^{2} - 0.0952 z - 0.9048 = 0

x^{2} - 8 x + 20 = 0

4.9 t^{2} - 11 t + 241 = 0

2 y^{2} - y + 2 = 0

What are the solutions to the equation -3x^2+9x-2=0 ?
The solutions to the equation -3x^2+9x-2=0 are x=(9-sqrt(57))/6 ,x=(9+sqrt(57))/6
Find the zeros of -3x^2+9x-2=0
The zeros of -3x^2+9x-2=0 are x=(9-sqrt(57))/6 ,x=(9+sqrt(57))/6