What are the solutions to the equation x^2=21^2+20^2 ?

The solutions to the equation x^2=21^2+20^2 are x=29,x=-29

Find the zeros of x^2=21^2+20^2

The zeros of x^2=21^2+20^2 are x=29,x=-29

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x^{2} = 2 1^{2} + 2 0^{2}

x = 29, x = - 29

Solution steps

x^{2} = 2 1^{2} + 2 0^{2}

Simplify

2 1^{2} + 2 0^{2} : 841

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 841, x = - 841

841 = 29

- 841 = - 29

x = 29, x = - 29

x, z = 3 x^{2} - 2 x y + y^{2} + 2 x + 2 y + 9

y^{2} - 5 y - 36 = 0

73 = 3 q^{2} - 40 q + 150

x, y = - 4 x^{2} - 4

5 x^{2} - 2 x + 13 = 18 x + 1

What are the solutions to the equation x^2=21^2+20^2 ?
The solutions to the equation x^2=21^2+20^2 are x=29,x=-29
Find the zeros of x^2=21^2+20^2
The zeros of x^2=21^2+20^2 are x=29,x=-29